E is any point on median AD of a `triangle ABC` . Show that ar (ABE) = ar (ACE).

E is any point on median AD of DeltaABC . If ar (DeltaABE) = 10 cm^2 then ar (DeltaACE) is :

E is any point on median AD of DeltaABC . If ar (DeltaABE) = 10 cm^2 then ar (DeltaACE) is :

If the medians of a triangleABC intersect at G, show that ar(AGB) = ar(AGC) = ar(BGC) = 1/3 ar(ABC)

If the medians of a triangleABC intersect at G, show that ar(AGB) = ar(AGC) = ar(BGC) = 1/3 ar(ABC)

P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar (APB) = ar (BQC).

If D, E, f are the mid-point of the sides of triangle ABC, prove that : ar(/_\DEF)=1/4 ar(/_\ABC) .

PQRS is a ||gm. L is any point on PS and M is any point on QR. Show that: ar(triangleQLR) = ar(triangleQPM) + ar(triangleSRM)

In Fig., E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD bot BC and EF bot AC, prove that triangleABD ~ triangle ECF. .

If E, F, G and H are respectively the mid-points of the sides of a parallelogram ABCD, show that ar(EFGH) =1/2 ar(ABCD).