Home
Class 9
MATHS
ABC and BDE are two equilateral triangle...

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Then ar (BDE)=`1/4` ar(ABC).

Promotional Banner

Topper's Solved these Questions

  • AREAS OF PARALLELOGRAMS AND TRIANGLES

    PSEB|Exercise EXAMPLE|4 Videos
  • CIRCLES

    PSEB|Exercise EXAMPLE|6 Videos

Similar Questions

Explore conceptually related problems

If ABC and BDE are two equilateral triangles such that D is the mid-point of BC, then find ar(triangleABC) : ar(triangleBDE)

Tick the correct answer and justify : ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Ratio of the areas of triangles ABC and BDE is

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE interesects BC at F, show that : ar(BDE) = 1/4 ar(ABC)

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE interesects BC at F, show that : ar(BDE) = 1/2 ar(BAE)

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE interesects BC at F, show that : ar(ABC) = 2ar(BEC)

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE interesects BC at F, show that : ar(FED) = 1/8 ar(AFC)

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE interesects BC at F, show that : ar(BFE) = ar(AFD)

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE interesects BC at F, show that : ar(BFE) = 2ar(FED)

In the figure ABCD and EFGD are two parallelograms and G is the mid-point of CD. Then ar(DPC) = 1/2 ar(EFGD)