Home
Class 9
MATHS
XY is a line parallel to side BC of tria...

XY is a line parallel to side BC of triangle ABC. If `BE II AC` and `CF II AB` meet XY at E and F respectively,show that ar (ABE) = ar (ACF).

Promotional Banner

Topper's Solved these Questions

  • AREAS OF PARALLELOGRAMS AND TRIANGLES

    PSEB|Exercise EXAMPLE|4 Videos
  • CIRCLES

    PSEB|Exercise EXAMPLE|6 Videos

Similar Questions

Explore conceptually related problems

A line parallel to BC of a triangle ABC, intersects AB and AC at D and E respectively. Prove that (AD//DB) =( AE//EC) .

E is any point on median AD of a triangle ABC . Show that ar (ABE) = ar (ACE).

In triangleABC , if L and M are the points on AB AC, respectivley such that LM||BC. Prove that ar(LOB) = ar(MOC)

A point is taken on the side BC of a parallelogram ABCD. AE and DC are produced to meet at F. Prove that : ar(ADF) = ar(ABFC)

In the fig. ABC, is an isosceles triangle in which AB=AC. Also D,E and F are mid point of BC, CB and AB respectively. Show that ADbotEF and AD is determined by EF

In triangleABC , it L and M are points on AB and AC respectively such that LM||BC. Prove that : ar(triangleLBC) = ar(triangleMBC)

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE interesects BC at F, show that : ar(BDE) = 1/4 ar(ABC)

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE interesects BC at F, show that : ar(ABC) = 2ar(BEC)

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE interesects BC at F, show that : ar(BFE) = ar(AFD)

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. If AE interesects BC at F, show that : ar(BFE) = 2ar(FED)