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The domain of f(x) = (x^(2))/(x^(2) - 3x...

The domain of f(x) = `(x^(2))/(x^(2) - 3x + 2)` is :

A

R

B

R - {1}

C

R - {1,2}

D

R - {-1,-2}

Text Solution

AI Generated Solution

The correct Answer is:
To find the domain of the function \( f(x) = \frac{x^2}{x^2 - 3x + 2} \), we need to determine the values of \( x \) for which the function is defined. The function is undefined when the denominator is equal to zero. ### Step-by-Step Solution: 1. **Identify the Denominator**: The denominator of the function is \( x^2 - 3x + 2 \). 2. **Set the Denominator Equal to Zero**: To find the values of \( x \) that make the function undefined, we set the denominator equal to zero: \[ x^2 - 3x + 2 = 0 \] 3. **Factor the Quadratic Equation**: We can factor the quadratic expression: \[ x^2 - 3x + 2 = (x - 1)(x - 2) \] 4. **Find the Roots**: Setting each factor to zero gives us the roots: \[ x - 1 = 0 \quad \Rightarrow \quad x = 1 \] \[ x - 2 = 0 \quad \Rightarrow \quad x = 2 \] 5. **Determine the Domain**: The function is undefined at \( x = 1 \) and \( x = 2 \). Therefore, the domain of \( f(x) \) includes all real numbers except these two values: \[ \text{Domain of } f(x) = \mathbb{R} \setminus \{1, 2\} \] ### Final Answer: The domain of \( f(x) = \frac{x^2}{x^2 - 3x + 2} \) is all real numbers except \( 1 \) and \( 2 \). ---
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