Find the number of words formed (meaningful or meaningless) by the letters of the words 'AGAIN' .If we write these words in a dictionary, find it `50^(th)` word.

Explanation

To solve the problem of finding the number of words formed by the letters of the word "AGAIN" and identifying the 50th word in alphabetical order, we can follow these steps:

### Step 1: Count the total number of arrangements
The word "AGAIN" consists of 5 letters where 'A' appears twice. To find the total number of distinct arrangements of these letters, we use the formula for permutations of multiset:

\[ \text{Total arrangements} = \frac{n!}{p_1! \times p_2! \times \ldots \times p_k!} \]
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