In the given figure, ABC is an equilateral triangle with co-ordinates of B and C as B(-3, 0) and C(3, 0). The co-ordinates of the vertex A are

The given figure shows an equilateral triangle OAB. If AB =2a units , find the co-ordinates of the vetices.

The slope of a median, drawn from the vertex A of the triangle ABC is -2. The co-ordinates of vertices B and C are respectively (-1, 3) and (3, 5). If the area of the triangle be 5 square units, then possible distance of vertex A from the origin is/are.

The base QR of an equilateral triangle PQR lies on X-axis. The co-ordinates of the point Q are (-4,0) and origin is the mid-point of the base. Find the co-ordinates of the points P and R.

The co-ordinates of three vertices of a parallelogram ABCD are A(1,0) , B(3,4) and C(1,2) . The co-ordinates of fourth vertex D are :

If one vertex of an equilateral triangle of side 'a' lie at the origin and the other lies on the line x-sqrt3 y = 0 , the co-ordinates of the third vertex are:

In the following diagram, write down : the co-ordinates of the points A, B and C.

From the given figure, find : the co ordinates of A, B and C.

Three vertices of a parallelogram ABCD are B (6,7) , C (8,3) and D (0,-1) . Find the co-ordinates of vertex A .

Given a line ABCD in which AB = BC = CD, B = (0, 3) and C = (1, 8). Find the co-ordinates of A and D.

In DeltaABC,angleA=90^(@) and the co-ordinates of points B and C are (2,-4) and (1,5) . Find the equation of the circumcircle of Delta ABC .