If the product of zeroes of the polynomial `x^(2)+5x-k` is 10, then find the value of k.

Explanation

To solve the problem, we need to find the value of \( k \) such that the product of the zeros of the polynomial \( x^2 + 5x - k \) is equal to 10.

### Step-by-step solution:

1. **Identify the polynomial**: The given polynomial is
\[ x^2 + 5x - k \]

2. **Recall the product of zeros formula**: For a quadratic polynomial of the form \( Ax^2 + Bx + C \), the product of the zeros (let's denote them as \( \alpha \) and \( \beta \)) can be calculated using the formula:
\[ \text{Product of zeros} = \frac{C}{A} \]
where \( C \) is the constant term and \( A \) is the coefficient of \( x^2 \).

3. **Identify coefficients**: In our polynomial:
- \( A = 1 \)
- \( B = 5 \)
- \( C = -k \)

4. **Apply the product of zeros formula**: According to the formula, the product of the zeros is:
\[ \alpha \cdot \beta = \frac{C}{A} = \frac{-k}{1} = -k \]

5. **Set up the equation**: We know from the problem statement that the product of the zeros is equal to 10. Therefore, we can write:
\[ -k = 10 \]

6. **Solve for \( k \)**: To find \( k \), we can rearrange the equation:
\[ k = -10 \]

### Final Answer:
The value of \( k \) is
\[ \boxed{-10} \]