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obtain all the zeroes of 3x^4+6x^3-2x^2-...

obtain all the zeroes of `3x^4+6x^3-2x^2-10x-5` if two of its zeroes are `sqrt(5/3)` and `-sqrt(5/3)`

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To find all the zeroes of the polynomial \( p(x) = 3x^4 + 6x^3 - 2x^2 - 10x - 5 \) given that two of its zeroes are \( \sqrt{\frac{5}{3}} \) and \( -\sqrt{\frac{5}{3}} \), we can follow these steps: ### Step 1: Write the Known Roots as Factors Since we know two roots, we can express them as factors of the polynomial: \[ (x - \sqrt{\frac{5}{3}})(x + \sqrt{\frac{5}{3}}) = x^2 - \left(\sqrt{\frac{5}{3}}\right)^2 = x^2 - \frac{5}{3} \] ### Step 2: Multiply by 3 to Eliminate the Fraction To make calculations easier, we can multiply the factor by 3: \[ 3\left(x^2 - \frac{5}{3}\right) = 3x^2 - 5 \] ### Step 3: Perform Polynomial Long Division Now, we will divide the polynomial \( p(x) \) by \( 3x^2 - 5 \) to find the other factor \( q(x) \). 1. Divide \( 3x^4 \) by \( 3x^2 \) to get \( x^2 \). 2. Multiply \( 3x^2 - 5 \) by \( x^2 \): \[ 3x^4 - 5x^2 \] 3. Subtract this from \( p(x) \): \[ (3x^4 + 6x^3 - 2x^2 - 10x - 5) - (3x^4 - 5x^2) = 6x^3 + 3x^2 - 10x - 5 \] 4. Now divide \( 6x^3 \) by \( 3x^2 \) to get \( 2x \). 5. Multiply \( 3x^2 - 5 \) by \( 2x \): \[ 6x^3 - 10x \] 6. Subtract this from the current polynomial: \[ (6x^3 + 3x^2 - 10x - 5) - (6x^3 - 10x) = 3x^2 - 5 \] 7. Now, divide \( 3x^2 \) by \( 3x^2 \) to get \( 1 \). 8. Multiply \( 3x^2 - 5 \) by \( 1 \): \[ 3x^2 - 5 \] 9. Subtract this from the current polynomial: \[ (3x^2 - 5) - (3x^2 - 5) = 0 \] ### Step 4: Write the Result of the Division The result of the division gives us: \[ p(x) = (3x^2 - 5)(x^2 + 2x + 1) \] ### Step 5: Factor the Quadratic Now we need to factor \( x^2 + 2x + 1 \): \[ x^2 + 2x + 1 = (x + 1)^2 \] ### Step 6: Find All Zeroes Now we can find all the zeroes of \( p(x) \): 1. From \( 3x^2 - 5 = 0 \): \[ 3x^2 = 5 \implies x^2 = \frac{5}{3} \implies x = \pm \sqrt{\frac{5}{3}} \] 2. From \( (x + 1)^2 = 0 \): \[ x + 1 = 0 \implies x = -1 \quad (\text{with multiplicity 2}) \] ### Final Answer Thus, the zeroes of the polynomial \( p(x) \) are: \[ \sqrt{\frac{5}{3}}, -\sqrt{\frac{5}{3}}, -1, -1 \]

To find all the zeroes of the polynomial \( p(x) = 3x^4 + 6x^3 - 2x^2 - 10x - 5 \) given that two of its zeroes are \( \sqrt{\frac{5}{3}} \) and \( -\sqrt{\frac{5}{3}} \), we can follow these steps: ### Step 1: Write the Known Roots as Factors Since we know two roots, we can express them as factors of the polynomial: \[ (x - \sqrt{\frac{5}{3}})(x + \sqrt{\frac{5}{3}}) = x^2 - \left(\sqrt{\frac{5}{3}}\right)^2 = x^2 - \frac{5}{3} \] ...
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