Find the equation of a line, passes through `(-1,2)` and perependicular to the line `2x+3y=1`.

Explanation

To find the equation of a line that passes through the point \((-1, 2)\) and is perpendicular to the line given by the equation \(2x + 3y = 1\), we can follow these steps:

### Step 1: Find the slope of the given line
The first step is to convert the equation of the line \(2x + 3y = 1\) into the slope-intercept form \(y = mx + c\), where \(m\) is the slope.

Starting with the equation:
\[
2x + 3y = 1
...