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if A =diag[2 -3 4], B= diag[3 1 -2 )and...

if A =diag[2 -3 4], B= diag[3 1 -2 )and C= diag[-1 2 2] then find
2A-B+3C.

Text Solution

Verified by Experts

`2A-B+3C`
`=2 diag [2" "-3" " 4]-Diag[3" "1" "-2]+3 diag[-1" "2" "-2]`
`=diag[4" " -6" "8] -diag[3" " 1" "-2]+diag [ -3 6 -6]`
= diag [ 4-3-3-6-1+6 8+2-6]
=diag [-2 -1 4].
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