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Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: `y=x^2+2x+C` : `yprime-2x-2=0`

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To verify that the function \( y = x^2 + 2x + C \) is a solution of the differential equation \( y' - 2x - 2 = 0 \), we will follow these steps: ### Step 1: Differentiate the function We start with the function: \[ y = x^2 + 2x + C \] Now, we differentiate \( y \) with respect to \( x \): ...
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