given that `tan(theta_1 + theta_2) = (tantheta_1 + tantheta_2)/(1-tantheta_1*tantheta_2)` find `(theta_1+theta_2)` when `tantheta_1 =1/2 , tantheta_2=1/3`

Explanation

To find \((\theta_1 + \theta_2)\) given that \(\tan(\theta_1 + \theta_2) = \frac{\tan \theta_1 + \tan \theta_2}{1 - \tan \theta_1 \tan \theta_2}\) and \(\tan \theta_1 = \frac{1}{2}\) and \(\tan \theta_2 = \frac{1}{3}\), we can follow these steps:

### Step 1: Substitute the values of \(\tan \theta_1\) and \(\tan \theta_2\)
We know:
\[ \tan(\theta_1 + \theta_2) = \frac{\tan \theta_1 + \tan \theta_2}{1 - \tan \theta_1 \tan \theta_2} \]
Substituting the values:
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