Home
Class 10
MATHS
The value of the expression cosec (75^(@...

The value of the expression cosec `(75^(@)+theta) - sec(15^@)-theta)-tan(55^(@)+theta) + cot(35^(@)-theta)` is

Text Solution

Verified by Experts

Given expression `="cosec "(75^(@)+theta)-sec(15^(@)-theta)-tan(55^(@)+theta)+cot(35^(@)-theta)`
`="cosec "[90^(@)-(15^(@)-theta)]-sec(15^(@)-theta)-tan[90^(@)-(35^(@)-theta)]+cot(35^(@)-theta)` " " `[:'"cosec "theta=sec(90^(@)-theta)ect.]`
`=sec(15^(@)-theta)-sec(15^(@)-theta)-cot(35^(@)-theta)+cot(35^(@)-theta)=0`
Promotional Banner

Topper's Solved these Questions

  • INTRODUCTION TO TRIGONOMETRY

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 8a|20 Videos
  • INTRODUCTION TO TRIGONOMETRY

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 8 B|22 Videos
  • INTRODUCTION TO TRIGONOMETRY

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Long Answer Questions|5 Videos
  • CONSTRUCTIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 11 B|10 Videos
  • LINEAR EQUATIONS IN TWO VARIABLES

    NAGEEN PRAKASHAN ENGLISH|Exercise Revision Exercise Long Answer Questions|8 Videos

Similar Questions

Explore conceptually related problems

Evaluate : cos e c(65^0+theta)-sec(25^0-theta)-tan(55^0-theta)+cot(35^0+theta)

Without using trigonometric tables, find the value of the following expression : (sec (90°-theta).cosec theta — tan (90°-theta) cot theta + cos^2 25° + cos^2 65°)/(3tan27^@.tan63^@)

Prove that : (tan^(2)theta)/(1+tan^(2)theta)+(cot^(2)theta)/(1+cot^(2)theta)=1

(sin(90^(@)-theta)sec(180^(@)-theta)sin(-theta))/(sin(180^(@)+theta)cot(360^(@)-theta)"cosec"(90^(@)+theta)) .

Prove that cos^(2)theta("cosec"^(2)theta-cot^(2)theta)=cos^(2)theta .

Prove that (sin theta- "cosec" theta )(cos theta- sec theta )=(1)/(tan theta + cot theta).

Evaluate : (cos^2(45 + theta) + cos^2(45 - theta))/(tan(60^@ + theta) tan(30^@ - theta)) + cosec(75^@ + theta) - sec(15^@ - theta)

If tan theta =(1)/(sqrt(7)) , find the value of ("cosec"^(2)theta-sec^(2)theta)/("cosec"^(2)theta+sec^(2)theta) .

(5) sec theta+tan theta=7 then sec theta-tan theta=?

(5) sec theta+tan theta=7 then sec theta-tan theta=?

NAGEEN PRAKASHAN ENGLISH-INTRODUCTION TO TRIGONOMETRY-Problems From NCERT/exemplar
  1. In P Q R , right-angled at Q ,\ P Q=3c m and P R=6c m . Determine ...

    Text Solution

    |

  2. Prove that : sqrt((1-cos^(2)theta)sec^(2)theta)=tantheta

    Text Solution

    |

  3. Prove (tantheta+2)(2tantheta+1)=5tantheta+2sec^2theta.

    Text Solution

    |

  4. If cosA+cos^(2)A=1, then prove that sin^(2)A+sin^(4)A=1.

    Text Solution

    |

  5. Prove the following identity: sec^4theta-sec^2theta=tan^4theta+tan^2th...

    Text Solution

    |

  6. Show that 1+cot^2alpha / (1+cosec alpha)=cosec alpha

    Text Solution

    |

  7. (sinalpha + cosalpha)(tanalpha + cotalpha) = secalpha + cosecalpha

    Text Solution

    |

  8. about to only mathematics

    Text Solution

    |

  9. If 2sin^(2)theta-cos^(2)theta=2, then find the value of theta.

    Text Solution

    |

  10. if tantheta+sectheta=l then prove that sectheta=(l^2+1)/(2l)

    Text Solution

    |

  11. If asintheta+bcostheta=c then prove that acostheta-bsintheta=sqrt(a^2+...

    Text Solution

    |

  12. If sintheta+costheta=pandsectheta+"cosec"theta=q then prove that q(p^(...

    Text Solution

    |

  13. Prove that : tantheta+tan(90^(@)-theta)=sectheta*sec(90^(@)-theta)

    Text Solution

    |

  14. Shown that : tan48^(@)tan23^(@)tan42^(@)tan67^(@)=1

    Text Solution

    |

  15. If tan A= cot B. prove that : A+B=90^(@)

    Text Solution

    |

  16. Express sin 67^(@)+cos75^(@) in terms of trigononmertic ratios of angl...

    Text Solution

    |

  17. If tan A=cot (A-18^(@)) where 2A is an acute angle , find the value of...

    Text Solution

    |

  18. If s e c4A=cos e c(A 20o) , where 4A is an acute angle, find the v...

    Text Solution

    |

  19. The value of the expression cosec (75^(@)+theta) - sec(15^@)-theta)-ta...

    Text Solution

    |

  20. If cos(alpha + beta)=0, then sin(alpha-beta) can be reduced to

    Text Solution

    |