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If sintheta=(7)/(25),then find the value...

If `sintheta=(7)/(25)`,then find the value of `sqrt((1-costheta)/(1+costheta))`.

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To solve the problem where \( \sin \theta = \frac{7}{25} \) and we need to find the value of \( \sqrt{\frac{1 - \cos \theta}{1 + \cos \theta}} \), we can follow these steps: ### Step 1: Use the Pythagorean Identity We know from the Pythagorean identity that: \[ \sin^2 \theta + \cos^2 \theta = 1 \] Given \( \sin \theta = \frac{7}{25} \), we can find \( \cos^2 \theta \): \[ \cos^2 \theta = 1 - \sin^2 \theta = 1 - \left(\frac{7}{25}\right)^2 \] ### Step 2: Calculate \( \sin^2 \theta \) Calculating \( \sin^2 \theta \): \[ \sin^2 \theta = \left(\frac{7}{25}\right)^2 = \frac{49}{625} \] ### Step 3: Substitute and Simplify Now substitute \( \sin^2 \theta \) back into the equation for \( \cos^2 \theta \): \[ \cos^2 \theta = 1 - \frac{49}{625} = \frac{625 - 49}{625} = \frac{576}{625} \] ### Step 4: Find \( \cos \theta \) Taking the square root to find \( \cos \theta \): \[ \cos \theta = \sqrt{\frac{576}{625}} = \frac{24}{25} \] ### Step 5: Substitute into the Expression Now we substitute \( \cos \theta \) into the expression we need to evaluate: \[ \sqrt{\frac{1 - \cos \theta}{1 + \cos \theta}} = \sqrt{\frac{1 - \frac{24}{25}}{1 + \frac{24}{25}}} \] ### Step 6: Simplify the Expression Calculating the numerator and denominator: \[ 1 - \frac{24}{25} = \frac{1}{25}, \quad 1 + \frac{24}{25} = \frac{49}{25} \] Thus, we have: \[ \sqrt{\frac{\frac{1}{25}}{\frac{49}{25}}} = \sqrt{\frac{1}{49}} = \frac{1}{7} \] ### Final Answer Therefore, the value of \( \sqrt{\frac{1 - \cos \theta}{1 + \cos \theta}} \) is: \[ \frac{1}{7} \]
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NAGEEN PRAKASHAN ENGLISH-INTRODUCTION TO TRIGONOMETRY-Exercise 8a
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  2. InDeltaABC,angleB=90^(@)and cosA=(9)/(41), then find all other trigono...

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  3. In DeltaABC,angleA=90^(@)andtanB=(5)/(6), then find all other trigono...

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  4. InDeltaPQR, angleR=90^(@)and"cosec"P=(13)/(5), then find all trigonome...

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  5. InDeltaABC,angleC=90^(@)andsecB=(5)/(4), then find all other trigono...

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  6. InDeltaABC,angleA=0=90^(@),AB=6cmandAC=8cm, then find the values of t...

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  7. In DeltaABC, angleB=90^(@),AB=24cmandAC=26cm then find the values of ...

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  8. If tan theta=2,then the find the value of (2sinthetacostheta)/(cos^(2)...

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  9. If sectheta=(3)/(2),then find value of (2costheta-tan^(2)theta)/(sin^(...

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  10. If sintheta=(1)/(3),then find the value of sintheta*cos^(2)theta+"cose...

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  11. If sin theta=(a)/(b),then find the value of (i) costheta, (ii) tant...

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  12. (i) If tantheta=(a)/(b),then find the value of (2sintheta-3costheta)/(...

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  13. If sectheta=(13)/(5),then show that (tantheta)/(1+tan^(2)theta)=(sinth...

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  14. If tantheta=(3)/(4),then find the value of sectheta+tantheta.

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  15. If tantheta=sqrt(2)-1,then find the value of cottheta.

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  16. If tanA=(1)/(sqrt(3))andtanB=sqrt(3),then find the value of cosAcosB-s...

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  17. If costheta=(3)/(4),then find the value of sinthetaandtantheta.

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  18. If cottheta=(12)/(5),then find the value ofsintheta*sectheta+costheta*...

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  19. If sintheta=(7)/(25),then find the value of sqrt((1-costheta)/(1+costh...

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  20. sintheta=(1)/(sqrt(2)),then find the value of 3sin ^(2)theta-4sin^(3)t...

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