if A= `45^o` then verify sin2A=2sinAcosA ,` cos2A=1-sin^2A`

cos^6A-sin^6A=cos2A(1-1/4sin^2 2A)

If A=30^(@) , then prove that : sin2A=2sinAcosA=(2tanA)/(1+tan^(2)A)

If A=30^(@) , then prove that : sin2A=2sinAcosA=(2tanA)/(1+tan^(2)A)

(1+sin2A-cos2A)/(1+sin2A+cos2A)=tanA

If A=15 deg , verify that 4sin2A.cos4A.sin6A=1

(i) Find maximum value of f(x)=|{:(1+sin^(2)x,cos^(2)x,4sin2x),(sin^(2)x,1+cos^(2)x,4sin2x),(sin^(2)x,cos^(2)x,1+4sin2x):}| . (ii) Let A,B and C be the angles of triangle such that Agt=Bgt=C. Find the minimum value of Delta where Delta=|{:(sin^(2)A,sinAcosA,cos^(2)A),(sin^(2) B,sinBcosB,cos^(2)B),(sin^(2)C,sinCcosC,cos^(2)C):}| .

If A =30^(@) ,verify that cos2A =cos^(2)A-sin^(2)A .

(sin^2 3A)/(sin^2A)-(cos^2 3A)/(cos^2A)=

If A =45^(@) ,then show that : cos 2A=cos^(2)A-sin^(2)A

If A=30^(@) , show that : (1+sin2A+cos2A)/(sinA+cosA)=2cosA .