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{:(0.4x + 0.3y = 1.7),(0.7x - 0.2y = 0.8...

`{:(0.4x + 0.3y = 1.7),(0.7x - 0.2y = 0.8):}`

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To solve the system of equations given by: 1. \(0.4x + 0.3y = 1.7\) (Equation 1) 2. \(0.7x - 0.2y = 0.8\) (Equation 2) we will follow these steps: ### Step 1: Eliminate the decimals To make calculations easier, we can multiply both equations by 10 to eliminate the decimals. - For Equation 1: \[ 10(0.4x + 0.3y) = 10(1.7) \implies 4x + 3y = 17 \] - For Equation 2: \[ 10(0.7x - 0.2y) = 10(0.8) \implies 7x - 2y = 8 \] Now we have the new system of equations: 1. \(4x + 3y = 17\) (Equation 3) 2. \(7x - 2y = 8\) (Equation 4) ### Step 2: Solve the equations Now we will solve these equations using the elimination method. #### Adding the equations: We can add Equation 3 and Equation 4: \[ (4x + 3y) + (7x - 2y) = 17 + 8 \] This simplifies to: \[ 11x + y = 25 \quad \text{(Equation 5)} \] #### Subtracting the equations: Next, we will subtract Equation 4 from Equation 3: \[ (4x + 3y) - (7x - 2y) = 17 - 8 \] This simplifies to: \[ -3x + 5y = 9 \quad \text{(Equation 6)} \] ### Step 3: Solve for one variable Now we will solve for \(y\) in terms of \(x\) using Equation 5: \[ y = 25 - 11x \quad \text{(Equation 7)} \] ### Step 4: Substitute into another equation Now we will substitute Equation 7 into Equation 6: \[ -3x + 5(25 - 11x) = 9 \] Expanding this gives: \[ -3x + 125 - 55x = 9 \] Combining like terms: \[ -58x + 125 = 9 \] Subtracting 125 from both sides: \[ -58x = 9 - 125 \] \[ -58x = -116 \] Dividing by -58: \[ x = \frac{-116}{-58} = 2 \] ### Step 5: Find the value of \(y\) Now we substitute \(x = 2\) back into Equation 7 to find \(y\): \[ y = 25 - 11(2) \] \[ y = 25 - 22 = 3 \] ### Final Solution Thus, the solution to the system of equations is: \[ x = 2, \quad y = 3 \]
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