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The largest angle of a triangle is twice...

The largest angle of a triangle is twice the sum of the other two. The smallest is one-fourth of the largest. Determine all the angles in degrees.

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To solve the problem, we will define the angles of the triangle and set up equations based on the information provided. ### Step 1: Define the angles Let: - \( x \) = the smallest angle - \( y \) = the second angle - \( z \) = the largest angle ### Step 2: Set up the equations From the problem statement, we have two key pieces of information: 1. The largest angle \( z \) is twice the sum of the other two angles: \[ z = 2(x + y) \quad \text{(Equation 1)} \] 2. The smallest angle \( x \) is one-fourth of the largest angle \( z \): \[ x = \frac{1}{4}z \quad \text{(Equation 2)} \] ### Step 3: Use the angle sum property of a triangle The sum of the angles in a triangle is always 180 degrees: \[ x + y + z = 180 \quad \text{(Equation 3)} \] ### Step 4: Substitute Equation 1 into Equation 3 Substituting \( z \) from Equation 1 into Equation 3: \[ x + y + 2(x + y) = 180 \] This simplifies to: \[ x + y + 2x + 2y = 180 \] \[ 3x + 3y = 180 \] Dividing the entire equation by 3: \[ x + y = 60 \quad \text{(Equation 4)} \] ### Step 5: Substitute Equation 4 into Equation 1 Now, substitute \( x + y = 60 \) back into Equation 1 to find \( z \): \[ z = 2(x + y) = 2(60) = 120 \] ### Step 6: Find the smallest angle using Equation 2 Now, substitute \( z = 120 \) into Equation 2 to find \( x \): \[ x = \frac{1}{4}z = \frac{1}{4}(120) = 30 \] ### Step 7: Find \( y \) using Equation 4 Now we can find \( y \) using Equation 4: \[ x + y = 60 \implies 30 + y = 60 \implies y = 60 - 30 = 30 \] ### Conclusion: All angles in degrees Thus, the angles of the triangle are: - Smallest angle \( x = 30^\circ \) - Second angle \( y = 30^\circ \) - Largest angle \( z = 120^\circ \) ### Final Answer The angles of the triangle are \( 30^\circ, 30^\circ, \) and \( 120^\circ \). ---
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NAGEEN PRAKASHAN ENGLISH-LINEAR EQUATIONS IN TWO VARIABLES -Exercise 3e
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