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2 men and 5 boys together can finish a p...

2 men and 5 boys together can finish a piece of work in 4 days, while 3 men and 6 boys can finish it in 3 days. Find the time taken by 1 man alone to finish the work and than taken by 1 boy alone.

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To solve the problem, we need to set up equations based on the information provided. Let's break it down step by step. ### Step 1: Define Variables Let: - \( X \) = the number of days one man alone can finish the work. - \( Y \) = the number of days one boy alone can finish the work. ### Step 2: Express Work Done in One Day The work done by one man in one day is \( \frac{1}{X} \) and the work done by one boy in one day is \( \frac{1}{Y} \). ### Step 3: Set Up the First Equation According to the problem, 2 men and 5 boys can finish the work in 4 days. Therefore, their combined work in one day is: \[ 2 \times \frac{1}{X} + 5 \times \frac{1}{Y} = \frac{1}{4} \] This simplifies to: \[ \frac{2}{X} + \frac{5}{Y} = \frac{1}{4} \tag{1} \] ### Step 4: Set Up the Second Equation Similarly, for 3 men and 6 boys who can finish the work in 3 days, we have: \[ 3 \times \frac{1}{X} + 6 \times \frac{1}{Y} = \frac{1}{3} \] This simplifies to: \[ \frac{3}{X} + \frac{6}{Y} = \frac{1}{3} \tag{2} \] ### Step 5: Clear the Fractions To eliminate the fractions, we can multiply both sides of equation (1) by \( 4XY \): \[ 4Y \cdot 2 + 4X \cdot 5 = XY \] This gives us: \[ 8Y + 20X = XY \tag{3} \] Now, multiply both sides of equation (2) by \( 3XY \): \[ 3Y \cdot 3 + 3X \cdot 6 = XY \] This gives us: \[ 9Y + 18X = XY \tag{4} \] ### Step 6: Rearranging the Equations From equations (3) and (4), we can rearrange them: \[ XY - 8Y - 20X = 0 \tag{5} \] \[ XY - 9Y - 18X = 0 \tag{6} \] ### Step 7: Subtract the Equations Now, subtract equation (6) from equation (5): \[ (XY - 8Y - 20X) - (XY - 9Y - 18X) = 0 \] This simplifies to: \[ Y - 2X = 0 \] Thus, we have: \[ Y = 2X \tag{7} \] ### Step 8: Substitute Back Substituting \( Y = 2X \) into equation (3): \[ 8(2X) + 20X = X(2X) \] This simplifies to: \[ 16X + 20X = 2X^2 \] \[ 36X = 2X^2 \] Dividing both sides by \( 2X \) (assuming \( X \neq 0 \)): \[ 18 = X \] So, \( X = 18 \). ### Step 9: Find Y Using equation (7): \[ Y = 2X = 2 \times 18 = 36 \] ### Conclusion Thus, the time taken by one man alone to finish the work is **18 days**, and the time taken by one boy alone to finish the work is **36 days**.
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NAGEEN PRAKASHAN ENGLISH-LINEAR EQUATIONS IN TWO VARIABLES -Exercise 3e
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  3. 2 men and 5 boys together can finish a piece of work in 4 days, while ...

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  4. A and B together can do a piece of work in 15 days. If 1 day's work of...

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  5. A takes 3 hours more than B to walk a distance of 30 km. But, if...

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  6. The boat goes 25 km upstream and 33 km downstream in 8 hours. It can a...

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  7. A boat travels for 7 hours. If it travels 4 hours downstream and 3 hou...

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  8. A sailor goes 8 km downstream in 40 minutes and returns in 1 hours....

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  9. Anshula walks 35 km partly at the rate 4 km/hour and Partly at 5 km/ho...

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  10. A bucket when filled (5)/(7) with water weights 12 kg and filled (3)/(...

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  11. Acids with 25% and 40% concentrations are mixed to get 60 litres of 30...

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  12. A person invested some amount at the rate of 12% simple interest and ...

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  13. rates?43. A milkman buys 15 litres milk partly at the rate of 12 per l...

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  14. Ved travels 600 km to his home partly by train and partly by car. H...

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  15. Students of a class are preparing for a drill and are made to stand...

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  16. A part of monthly hostel charges is fixed and the remaining depends on...

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  17. The ratio of incomes of A and B is 9 : 7 and the ratio of their expend...

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  18. Mr. Mohit has decided to walk on a treadmill for a fixed distance. Fir...

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  19. It takes 12 hours to fill a swimming pool using two pipes . If the pip...

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