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Solve x + y = 10 and x - y = 4....

Solve x + y = 10 and x - y = 4.

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To solve the system of equations \( x + y = 10 \) and \( x - y = 4 \), we can use the substitution method. Here’s a step-by-step solution: ### Step 1: Identify the equations We have two equations: 1. \( x + y = 10 \) (Equation 1) 2. \( x - y = 4 \) (Equation 2) ### Step 2: Solve one equation for one variable Let's solve Equation 1 for \( x \): \[ x = 10 - y \] We will call this Equation 3. ### Step 3: Substitute the value of \( x \) into the second equation Now, we substitute the value of \( x \) from Equation 3 into Equation 2: \[ (10 - y) - y = 4 \] ### Step 4: Simplify the equation Combine like terms: \[ 10 - y - y = 4 \\ 10 - 2y = 4 \] ### Step 5: Solve for \( y \) Now, isolate \( y \): \[ -2y = 4 - 10 \\ -2y = -6 \\ y = \frac{-6}{-2} \\ y = 3 \] ### Step 6: Substitute \( y \) back to find \( x \) Now that we have \( y \), substitute it back into Equation 1 to find \( x \): \[ x + 3 = 10 \\ x = 10 - 3 \\ x = 7 \] ### Final Solution The solution to the system of equations is: \[ x = 7, \quad y = 3 \]
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