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Factorize : (x-2y)^3+(2y-3z)^3+(3z-x)^3...

Factorize : `(x-2y)^3+(2y-3z)^3+(3z-x)^3`

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Let x-2y=a, 2y-3z=b and 3z-x=c
`therefore " " a+b+c=x-2y+2y-3z+3z-x=0`
`implies " " a^(3)+b^(3)+c^(3)=3abc`
Hence, `(x-2y)^(3)+(2y--3z)^(3)+(3z-x)^(3)=3(x-2y)(2y-3z)(3z-x)`
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