If `h , c ,V` are respectively the height, the curved surface and the volume of a cone, prove that `3piV h^3-C^2h^2+9V^2=0.`

Explanation

To prove that \(3\pi V h^3 - C^2 h^2 + 9V^2 = 0\), where \(h\) is the height, \(C\) is the curved surface area, and \(V\) is the volume of a cone, we will follow these steps:

### Step 1: Write the formulas for the volume and curved surface area of a cone.
The volume \(V\) of a cone is given by:
\[ V = \frac{1}{3} \pi r^2 h \]
The curved surface area \(C\) of a cone is given by:
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