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Three cubes of metal whose edges are in the ratio 3:4:5 are melted down into a single cube whose diagonal is `12sqrt(3)\ c m` . Find the edges of three cubes.

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To solve the problem step by step, we will follow the reasoning presented in the video transcript. ### Step 1: Define the edges of the cubes Let the edges of the three cubes be represented as: - First cube: \(3x\) - Second cube: \(4x\) - Third cube: \(5x\) ### Step 2: Calculate the volume of each cube The volume \(V\) of a cube is given by the formula \(V = a^3\), where \(a\) is the length of an edge. Therefore, the volumes of the three cubes can be calculated as follows: - Volume of the first cube: \(V_1 = (3x)^3 = 27x^3\) - Volume of the second cube: \(V_2 = (4x)^3 = 64x^3\) - Volume of the third cube: \(V_3 = (5x)^3 = 125x^3\) ### Step 3: Total volume of the three cubes The total volume of the three cubes when melted down is: \[ V_{total} = V_1 + V_2 + V_3 = 27x^3 + 64x^3 + 125x^3 = (27 + 64 + 125)x^3 = 216x^3 \] ### Step 4: Volume of the new cube The volume of the new cube formed from the melted metal is also given by the formula for the volume of a cube: \[ V_{new} = a^3 \] where \(a\) is the edge of the new cube. ### Step 5: Relate the edge of the new cube to its diagonal We know the diagonal \(d\) of the cube is given as \(12\sqrt{3}\) cm. The diagonal of a cube can be calculated using the formula: \[ d = a\sqrt{3} \] Setting this equal to the given diagonal: \[ a\sqrt{3} = 12\sqrt{3} \] Dividing both sides by \(\sqrt{3}\): \[ a = 12 \text{ cm} \] ### Step 6: Calculate the volume of the new cube Now we can find the volume of the new cube: \[ V_{new} = a^3 = 12^3 = 1728 \text{ cm}^3 \] ### Step 7: Set the volumes equal Since the total volume of the three cubes equals the volume of the new cube: \[ 216x^3 = 1728 \] ### Step 8: Solve for \(x\) Dividing both sides by 216: \[ x^3 = \frac{1728}{216} = 8 \] Taking the cube root: \[ x = 2 \] ### Step 9: Find the edges of the original cubes Now we can find the edges of the three cubes: - Edge of the first cube: \(3x = 3 \times 2 = 6 \text{ cm}\) - Edge of the second cube: \(4x = 4 \times 2 = 8 \text{ cm}\) - Edge of the third cube: \(5x = 5 \times 2 = 10 \text{ cm}\) ### Final Answer The edges of the three cubes are: - First cube: \(6 \text{ cm}\) - Second cube: \(8 \text{ cm}\) - Third cube: \(10 \text{ cm}\) ---
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NAGEEN PRAKASHAN ENGLISH-SURFACE AREA AND VOLUME-Exercise 13a
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