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A feild is 70 m long and 40 m broad. In ...

A feild is 70 m long and 40 m broad. In one corner of the field, a pit which is 10 m long, 8 m broad and 5 m deep, has been dug out. The earth taken out of it is evenly spread over the remaining part of the field. Find the rise in the level of the field.

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To find the rise in the level of the field after the earth from the pit is spread evenly over the remaining part of the field, we can follow these steps: ### Step 1: Calculate the area of the rectangular field. The area of the field can be calculated using the formula: \[ \text{Area} = \text{Length} \times \text{Breadth} \] Given: - Length = 70 m - Breadth = 40 m Calculating the area: \[ \text{Area} = 70 \, \text{m} \times 40 \, \text{m} = 2800 \, \text{m}^2 \] ### Step 2: Calculate the volume of the pit. The volume of the pit can be calculated using the formula: \[ \text{Volume} = \text{Length} \times \text{Breadth} \times \text{Depth} \] Given: - Length = 10 m - Breadth = 8 m - Depth = 5 m Calculating the volume: \[ \text{Volume} = 10 \, \text{m} \times 8 \, \text{m} \times 5 \, \text{m} = 400 \, \text{m}^3 \] ### Step 3: Calculate the area of the pit. The area of the pit can be calculated using the formula: \[ \text{Area} = \text{Length} \times \text{Breadth} \] Using the same dimensions as above: \[ \text{Area of the pit} = 10 \, \text{m} \times 8 \, \text{m} = 80 \, \text{m}^2 \] ### Step 4: Calculate the remaining area of the field. The remaining area of the field after the pit is dug can be calculated as: \[ \text{Remaining Area} = \text{Total Area} - \text{Area of the Pit} \] Calculating the remaining area: \[ \text{Remaining Area} = 2800 \, \text{m}^2 - 80 \, \text{m}^2 = 2720 \, \text{m}^2 \] ### Step 5: Calculate the rise in the level of the field. Let the rise in the level of the field be \( h \). The volume of earth taken out from the pit is spread over the remaining area, so we can use the formula: \[ \text{Volume} = \text{Area} \times \text{Height} \] Thus: \[ 400 \, \text{m}^3 = 2720 \, \text{m}^2 \times h \] Now, solving for \( h \): \[ h = \frac{400 \, \text{m}^3}{2720 \, \text{m}^2} \] Calculating \( h \): \[ h = \frac{400}{2720} \approx 0.147 \, \text{m} \] ### Step 6: Convert \( h \) to centimeters. To convert meters to centimeters, we multiply by 100: \[ h = 0.147 \, \text{m} \times 100 = 14.7 \, \text{cm} \] ### Final Answer: The rise in the level of the field is approximately \( 0.147 \, \text{m} \) or \( 14.7 \, \text{cm} \). ---
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NAGEEN PRAKASHAN ENGLISH-SURFACE AREA AND VOLUME-Exercise 13a
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  14. A feild is 70 m long and 40 m broad. In one corner of the field, a pit...

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  15. If V is the volume of a cuboid of dimensions a , b , ca n dS is its...

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  16. The areas of three adjacent faces of a cuboid are x, y and z. If the v...

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  17. If each edge of a cube is increased by 25%, then the percentage incr...

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  18. Find the percentage increase in the surface area of a cube if each sid...

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  20. A tank measures 2 m long 1.6 m wide and 1m depth water is there up to ...

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