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X and Y are points on the sides AB and B...

X and Y are points on the sides AB and BC respectively of `triangleABC` such that XY||AC and XY divides `triangleABC` into two parts in area , find `(AX)/(AB)`

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To solve the problem, we need to find the ratio \( \frac{AX}{AB} \) given that \( XY \parallel AC \) and that it divides the area of triangle \( ABC \) into two parts. ### Step-by-Step Solution: 1. **Understanding the Problem**: We have triangle \( ABC \) with points \( X \) on side \( AB \) and \( Y \) on side \( BC \) such that line segment \( XY \) is parallel to side \( AC \). This means that triangle \( AXY \) is similar to triangle \( ABC \). 2. **Area Relationship**: ...
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