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In P Q R ,\ \ Q M|P R and P R^2-P Q^2=Q...

In ` P Q R ,\ \ Q M_|_P R` and `P R^2-P Q^2=Q R^2` . Prove that `Q M^2=P MxxM R`

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To solve the problem, we need to prove that \( QM^2 = PM \times MR \) given that in triangle \( PQR \), \( QM \perp PR \) and \( PR^2 - PQ^2 = QR^2 \). ### Step-by-Step Solution: 1. **Understanding the Given Information**: - We have triangle \( PQR \) with \( QM \) perpendicular to \( PR \). - The equation \( PR^2 - PQ^2 = QR^2 \) suggests that we can apply the Pythagorean theorem. ...
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