Find the point on the curve `y=x^(2)+1` at which the tangent drawn makes an angle of `45^(@)` from X-axis.

Explanation

To find the point on the curve \( y = x^2 + 1 \) where the tangent makes an angle of \( 45^\circ \) with the x-axis, we can follow these steps:

### Step 1: Differentiate the curve
The first step is to find the derivative of the curve, which gives us the slope of the tangent line at any point on the curve.

\[ y = x^2 + 1 \]
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