Find the equation of tangent of the curve `yx^(2)+x^(2)-5x+6=0` at that point at which curve crosses the X-axis.

Explanation

To find the equation of the tangent to the curve \( yx^2 + x^2 - 5x + 6 = 0 \) at the points where the curve crosses the x-axis, we can follow these steps:

### Step 1: Find the points where the curve crosses the x-axis
The curve crosses the x-axis where \( y = 0 \). Therefore, we substitute \( y = 0 \) into the equation:

\[ 0 \cdot x^2 + x^2 - 5x + 6 = 0 \]
...