Find a point on the curve `y=3x^(2)-2x - 4 ` at which the tangent is parallel to the line `10x-y+7=0`.

Explanation

To find a point on the curve \( y = 3x^2 - 2x - 4 \) where the tangent is parallel to the line \( 10x - y + 7 = 0 \), we can follow these steps:

### Step 1: Find the slope of the given line
First, we need to rewrite the equation of the line in slope-intercept form \( y = mx + c \):
\[ 10x - y + 7 = 0 \implies y = 10x + 7 \]
From this equation, we can see that the slope \( m \) of the line is \( 10 \).
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