Find the slope of the tangent to the curve `y=x^3-3x+2` at the point whose x-coordinate is 3.

Explanation

To find the slope of the tangent to the curve \( y = x^3 - 3x + 2 \) at the point where the x-coordinate is 3, we will follow these steps:

### Step 1: Differentiate the function
We need to find the derivative of the function \( y \) with respect to \( x \). The derivative \( \frac{dy}{dx} \) gives us the slope of the tangent line at any point on the curve.

\[ y = x^3 - 3x + 2 \]
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