Find a point on the curve `y=(x-2)^2`at which the tangent is parallel to the chord joining the points (2, 0) and (4, 4).

Explanation

To find a point on the curve \( y = (x - 2)^2 \) at which the tangent is parallel to the chord joining the points \( (2, 0) \) and \( (4, 4) \), we can follow these steps:

### Step 1: Find the slope of the chord
The slope of the chord can be calculated using the formula:
\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \]
Here, the points are \( (2, 0) \) and \( (4, 4) \). Thus, we have:
...