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Evaluate: inte^xx/((x+1)^2)dx...

Evaluate: `inte^xx/((x+1)^2)dx`

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` int (x.e^(x))/((1+x)^(2))dx`
` =int({(1+x)-1}}/ ((1+x)^(2))e^(x).dx`
`= int (1+x)/((1+x)^(2)).e^(x)dx-int(1)/((1+x)^(2))e^(x) dx`
`= int (1)/(1+x).e^(x)dx - int(1)/((1+x)^(2)).e^(x) dx`
`=(1)/(1+x).int e^(x)dx- int {(d)/(dx).(1)/(1+x).int e^(x)dx}dx`
`- int (1)/((1+x)^(2)).e^(x)dx`
` =(e^(x))/(1+x) - int (-1)/((1+x)^(2)) .e^(x) dx- int(1)/((1+x)^(2)).e^(x)dx+C`
`=(e^(x))/(1+x)+int(1)/((1+x)^(2)).e^(x)dx`
`-int(1)/((1+x)^(2)) .e^(x) dx+C`
`=(e^(x))/(1+x)+C`
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