`int sinx/sin(x-alpha)dx=Ax+B log (sin(x-alpha))+C` then find out `(A ,B)`

Explanation

`"Let " x- a=t`
`rArr " "dx=dt`
`int(sinx)/(sin(x-a)) dx= int(sin (t+a))/(sin t) dt`
`= int (sin t cos a + cos t sin a)/(sin t)dt``=int (cos a +sin a cot t) dt`
` = cos a int 1 dt + sin a int cot t dt`
`= t cos a+ sin a log |sin t|+c_(1)`
`=(x-a) cos a`
`+sin a . log |sin (x-a)|+C_(1)`
`=x cos a + sin a log `
`|sin (x-a)|+C_(1)-a cos a`
`=x cos a + sin a log |sin (x-a)|+C`
`" where " c=c_(1) -a cos a`