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int(0)^(1) sin^(-1) x dx =(pi)/(2) -1...

`int_(0)^(1) sin^(-1) x dx =(pi)/(2) -1`

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To solve the integral \( I = \int_0^1 \sin^{-1} x \, dx \) and prove that it equals \( \frac{\pi}{2} - 1 \), we can follow these steps: ### Step 1: Set up the integral Let \[ I = \int_0^1 \sin^{-1} x \, dx \] ...
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