Home
Class 12
MATHS
Let A=R-{3}a n dB=R-{1}dot Consider the ...

Let `A=R-{3}a n dB=R-{1}dot` Consider the function `f: Avec` defined by `f(x)=(x-2)/(x-3)dot` Show that is one-one and onto and hence find `f^(-1)`

Promotional Banner

Topper's Solved these Questions

  • RELATIONS AND FUNCTIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercies 1c|9 Videos
  • RELATIONS AND FUNCTIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercies 1d|10 Videos
  • RELATIONS AND FUNCTIONS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercies 1a|18 Videos
  • PROBABIILITY

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exercise|19 Videos
  • THREE-DIMENSIONAL GEOMETRY

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exercise|23 Videos

Similar Questions

Explore conceptually related problems

Let A=R-{3} and B=R-[1]dot Consider the function f: AvecB defined by f(x)=((x-2)/(x-3))dot Show that f is one-one and onto and hence find f^(-1)

Let A=R-{3} and B=R-[1]dot Consider the function f: AvecB defined by f(x)=((x-2)/(x-3))dot Show that f is one-one and onto and hence find f^(-1)

Let A = R - {3} and B = R - {1}, consider the function f A rarr B defined by =((x-2)/(x-3)) Show that f'is one-one and onto and hence find/

Let the function f:R→R be defined by f(x)=cosx,∀x∈R. Show that f is neither one-one nor onto

Let A = R - {3} and B = R - {1} . Consider the function f: A->B defined by (x)=((x-2)/(x-3)) . Is f one-one and onto? Justify your answer.

Show that the function f in A = R - {2/3} defined as f(x) = (4x+3)/(6x-4) is one one and onto. Hence find f^(-1)

Let A = R - {2}, B = R - {1}. If f : ArarrB is a function defined by f(x) = (x-1)/(x-2) , show that f is one-one and onto.

If A=R-{3} and B=R-{1} and f:AtoB is a mapping defined by f(x)=(x-2)/(x-3) show that f is one-one onto function.

Let f: R->R be defined by f(x)=3x-7 . Show that f is invertible and hence find f^(-1) .

If a function f: R to R is defined as f(x)=x^(3)+1 , then prove that f is one-one onto.

NAGEEN PRAKASHAN ENGLISH-RELATIONS AND FUNCTIONS -Exercies 1b
  1. f: R to R is a function where f(x)= 2x-3 . Check whether f is noe -on...

    Text Solution

    |

  2. The relation R={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)} on set A={1,2,3} ...

    Text Solution

    |

  3. Show that the function f: N->N , given by f(x)=2x , is one-one but not...

    Text Solution

    |

  4. The function f:R to R defined as f(x)=x^(2). The function f is

    Text Solution

    |

  5. If Q is the set of rational numbers, then prove that a function f: Q t...

    Text Solution

    |

  6. If R is the set of real numbers then prove that a function f: R to R ...

    Text Solution

    |

  7. Prove that the function f: R^(+) to R which is defined as f(x)=log(e)...

    Text Solution

    |

  8. If R is the set of real numbers prove that a function f: R -> R,f(x)=...

    Text Solution

    |

  9. A function f: R to R is defined as f(x)=4x-1, x in R, then prove that...

    Text Solution

    |

  10. Let A=R-{3}a n dB=R-{1}dot Consider the function f: Avec defined by f(...

    Text Solution

    |

  11. Let the function f:R to R be defined by f(x)=cos x, AA x in R. Show th...

    Text Solution

    |

  12. If a function f: R to R is defined as f(x)=x^(3)+1, then prove that f...

    Text Solution

    |

  13. If A={x : x in R, (-pi)/(2) le x le (pi)/(2)}, B={y : y in R, -1 le y ...

    Text Solution

    |

  14. If f: R to R and g : R to R be two functions defined as respectivel...

    Text Solution

    |

  15. Function f: R to R and g : R to R are defined as f(x)=sin x and g(x) ...

    Text Solution

    |

  16. If f: R to R and g: R to R be two functions defined as f(x)=2x+1 an...

    Text Solution

    |

  17. If f and g are two functions from R to R which are defined as f(x)=x^(...

    Text Solution

    |

  18. If f: R to R and g: R to R be two functions defined as f(x)=x^(2) an...

    Text Solution

    |

  19. If f: R to R defined as f(x)=3x+7, then find f^(-1)(-2)

    Text Solution

    |

  20. If Q is the set of rational numbers and a function f:Q to Q is define...

    Text Solution

    |