Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 20 litres. How much heat is absorbed and how much work is done in the expansion?

Explanation

Heat absorbed = 0 P of gas =10 atm
Because the given process is isothermal `" "P_(Exp)=0`
`triangleU=0 " "V_(1)=2 lit`
`q+w=0 " "V_(2)="20 lit"`
`q=-w " "v_(2)=20 lit`
q=-w
`=p_("ex") (v_(2)-v_(1))`
`=P_(ex) (20-2)`
=0(18)=0
q=0 work done also zero, W=0