Write the IUPAC names of the compounds i-iv from their given structures.
(i) `overset(1)(C)H_(3)-overset(2)(C)H_(2)-underset(OH)underset("| ")overset("3 ")(CH)-overset(4)(C)H_(2)-overset(5)(C)H_(2)-underset(CH_(3))underset("| ")overset("6 ")(CH)-overset(7)(C)H_(2)-overset(8)(C)H_(3)`
(ii) `underset(6)(C)H_(3)-underset(5)(C)H_(2)-underset(4)overset(O)overset(||)(C)-underset(3)(C)H_(2)-underset(2)overset(O)overset(||)(C)-underset(1)(C)H_(3)`
(iii) `underset(6)(C)H_(3)-underset(5)overset(O)overset(||)(C)-underset(4)(C)H_(2)-underset(3)(C)H_(2)-underset(2)(C)H_(2)-underset(1)(C)OOH`
(iv) `underset(6)(C)H-=underset(5)(C)-underset(4)(C)H=underset(3)(C)H-underset(2)(C)H=underset(1)(C)H_(2)`

Explanation

The functional group present is an alcohol (OH). Hence the suffix is .-01.. The longest chain containing -OH has eight carbon atoms. Hence the corresponding saturated hydrocarbon is octane.
The-OH is on carbon atom 3. In addition, a methyl group is attached at `6^(th)` carbon. Hence, the systematic name of this compound is 6-Methyloctan-3-ol.