Compute the heat generated while transforming 96,000 coulombs of charge in one hour through a potential difference of 50 V.

Explanation

Here, Q = 96,000 C, `t = 1 "hour" = 60 xx 60 s` and V = 50 V
Current `I= (Q)/(t)= (96000)/(60 xx 60)= (80)/(3)A`
Resistance,`R = (V)/(I)= (50 xx3)/(80)= (15)/(8)Omega`
Heat produced, `H= I^(2)Rt`
`= (80)/(3) xx(80)/(3) xx (15)/(8) xx 60 xx 60`
= 4800000J
= 4800kJ