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Find (dy)/(dx) if x^(y)=y^(cosx)...

Find `(dy)/(dx)` if `x^(y)=y^(cosx)`

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The correct Answer is:
`:.(dy)/(dx)=(y^(x)logy-x^(y-1)y-(1)/(2))/(x^(y)logx-y^(x-1)x)`
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