int0^2[x^2]dx...

`int_0^2[x^2]dx`

Text Solution

Verified by Experts

The correct Answer is:

`2-sqrt2`

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ARIHANT PRAKASHAN-INTEGRATION -TOPIC 2 (PRACTISE QUESTIONS) (4 MARK QUESTIONS)

Evaluate int-1^2 {|x\|+[x]}dx
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Evaluate int0^1 x^7 sqrt(((1+x^2)/(1-x^2))) dx, 0 le x le 1
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int0^2[x^2]dx
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Evaluate int0^(pi/2)(sqrt(sinx))/(sqrt(sinx)+sqrt(cos x))dx
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Evaluate int(-3//5)^(3//5) [2x] dx
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Evaluate int0^8|x-5|dx
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int0^(pi/2) (sin^2xdx)/(sinx+cosx)
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Evaluate : int(0) ^(pi/4) dx/cos x (cos x + sin x).
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Evaluate:int0^4|8-3x|dx
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Evaluate int0^1 (1+x^2) dx
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Evaluate int0^(pi) sinxdx
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Evaluate int0^(2pi) cos x dx
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Evaluate int0^3 x^2.e^(x^3) dx
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Evaluate int0^(pi//2) ( cos x)/ (1+sinx) dx
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Evaluate int0^7 (dx)/ (sqrt(x+2)+sqrt(x+7))
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Evaluate int0^(pi//2) (cos x)/ ((2+ sin x)(3+sin x))dx
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Evaluate int1^0 (tan^-1 x)/(1+x^2) dx
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Evaluate int x log (1+x) dx
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Evaluate int1^2 (dx)/(16-x^2)
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Evaluate int0^(pi//2) cos x dx
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