Find int0^3 (3x+1)/(9x^2-1) dx...

Find `int_0^3 (3x+1)/(9x^2-1) dx`

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The correct Answer is:

`pi//12`

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ARIHANT PRAKASHAN-INTEGRATION -TOPIC TEST 2

Evaluate int0^2 sqrt(4-x^2) dx
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Find int(-pi//4)^(pi//4) sin^3 x dx
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Evaluate int0^pi cos^2 x dx
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Evaluate the integral int(0)^(2pi)(1)/(1+e^(sinx))dx.
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int0^(3/2)[2x]dx
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int0^ax^3(a^2-x^2)^(5/2)dx
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Evaluate int0^(-pi//2) (4+5 sin x) dx
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Find int0^(pi//2) cos^12 x dx
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int0^(pi/4) xsinxdx
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int(-2)^1((abs(x))+x)dx
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Find the value of the integral int(-4)^4 (ax^3+bx+c) dx
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Find int(-2)^2 |1-x^2|dx
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Evaluate int(-1//2)^(1//2)[((x+1)/(x-1))^2 +((x-1)/(x+1))^2-2]^(1//2) ...
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Find the value of int-pi^(pi) 2 sin xdx
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Find int0^3 (3x+1)/(9x^2-1) dx
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Find the value of int0^(pi//2) |sin(x-pi//4)|dx
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Evaluate int0^1 cot (1+x)dx
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Evaluate int(0)^1e^x dx
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I=int0^4(x^2+2x+4)dx
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