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If "cos"^(-1)(x/a) ="cos"^-1(y/b) = thet...

If `"cos"^(-1)(x/a) ="cos"^-1(y/b) = theta, "prove that" x^2/a^2 -(2xy)/(ab) "cos" theta +y^2/b^2 ="sin"^2 theta.`

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The correct Answer is:
`=1`
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