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Find the value of sin^(-1) [ cos ((3pi)/...

Find the value of `sin^(-1) [ cos ((3pi)/(5) ) ]`.

Text Solution

Verified by Experts

The correct Answer is:
`= - (pi)/(2) [ because sin^(-1) (sin theta) = theta, theta in [- (pi)/(2) , (pi)/(2) ]]`
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