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If 2cos theta +sin theta = 1, (theta pi ...

If `2cos theta +sin theta = 1, (theta pi (4k+1)pi//2, k in I)` then `7cos theta+6sin theta` is equal to :

A

`1//2`

B

2

C

`11//2`

D

`46//5`

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The correct Answer is:
b
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