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If cos alpha+cos beta=a, sin alpha+sin b...

If `cos alpha+cos beta=a, sin alpha+sin beta=b and theta` is the arithmetic mean between `alpha and beta` then `sin 2 theta+cos 2 theta` is equal to

A

`(a+b)^(2)//(a^(2)+b^(2))`

B

`(a-b)^(2)//(a^(2)+b^(2))`

C

`(a^(2)-b^(2))//(a^(2)+b^(2))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
d
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