In the given reaction `CH_3-CH_2-Broverset(Na//"dryether")rarr` Product, product will be

Options

A. Pure n - butane
B. Mixture of butane and hydrogen
C. Mixture of butane, ethene and ethane
D. Mixture of ethene and ethane

Answer

To solve the given question regarding the reaction of CH3-CH2-Br with Na in dry ether, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactant is CH3-CH2-Br (bromoethane) and the reagents are sodium (Na) and dry ether.

2. **Understand the Reaction Conditions**: The presence of sodium and dry ether suggests that we are dealing with a Wurtz reaction, which typically involves the coupling of alkyl halides to form alkanes.

3. **Mechanism of the Reaction**: The reaction proceeds through a free radical mechanism:
- Sodium (Na) donates an electron to the bromoethane (CH3-CH2-Br), generating a free radical (CH3-CH2•) and sodium bromide (NaBr).
- This free radical can then react with another free radical or with itself.

4. **Possible Free Radical Combinations**:
- The CH3-CH2• radical can couple with another CH3-CH2• radical to form butane (C4H10).
- Alternatively, the CH3-CH2• radical can react with hydrogen atoms (H•) to form ethane (C2H6).
- There is also a possibility of forming ethene (C2H4) through elimination reactions.

5. **Final Products**: The possible products from this reaction are:
- Butane (C4H10)
- Ethane (C2H6)
- Ethene (C2H4)

6. **Conclusion**: Therefore, the final answer is that the products formed will be a mixture of butane, ethane, and ethene.