The total profit y (in rupee) of a drug company from the manufacture and sale of x bottles of drug is given by `y=(-x^2)/300+2x-50`. How many bottles of drug must the company sell to obtain maximum profit.

The total profit y (in rupee) of a drug company from the manufacture and sale of x bottles of drug is given by y=(-x^2)/300+2x-50 . What is the maximum profit?

The total revenue is Rupees received from the sale of x units of a product is given by R(x)=13x^2+26x+5 . Find the marginal revenue when x = 7

Find the maximum profit that a company can make, if the profit function is given by p(x)=41-24x-6x^2

Find the maximum profit that a company can make, if the profit function is given by p(x)=41-72x-18x^2

The total revenue in Rupees received from the sale of x units of a product is given by R(x)=3 x^2+36 x+5 . The marginal revenue, when x=15 is a)116 b)96 c)90 d)126

Find the maximum profit that a company can make, if the profit function is given by p(x)=41-24 x-18 x^2

The total revenue in rupees received from the sale of x units of a product is given by R(x) = 13x^(2) + 26x + 15 . Then, the marginal revenue in rupees, when x = 15 is a)116 b)126 c)136 d)416

Manufacturer can sell, x items at a price of rupees (5-(x/100)) each. The cost price of x items is Rs. (x/5+500) . Find the number of items he should sell to earn maximum profit:

The total revenue is Rupees received from the sale of x units of a product is given by R(x)=3x^2+36x+5 . Find the marginal revenue, when x = 5, where by marginal revenue we mean the rate of change of total revenue with respect to the number of items sold at an instant.

A point of inflection of the curye given by y = x ^(3) - 6x ^(2) + 12 x + 50 occurs when