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A body, under the action of a force vecF...

A body, under the action of a force `vecF = 6hati - 8hatj + 10 hatk` acquires an acceleration of `1 m//s^(2)`. The mass of this body must be:

A

10 kg

B

20 kg

C

`10sqrt(2)` kg

D

`2sqrt(10) kg`

Text Solution

Verified by Experts

The correct Answer is:
C
Magnitude of force `(6hati - 8hatj + 10 hatk)` N
`=sqrt((6)^(2) + (8)^(2) + (10)^(2)) = 10sqrt(2) N`
Acceleration `=1 ms^(-2)`. So mass `= 10sqrt(2) kg`
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