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A block of mass 2 kg is placed on the fl...

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 3 N is applied on the block as shown in figure. The force of friction between the block and the floor is (Take `g=10 m s^(-2)`)

A

1.5 N

B

3 N

C

4 N

D

2.5 N

Text Solution

Verified by Experts

The correct Answer is:
D
`fs = musR = 0.4 xx 2 xx 9.8 = 7.8 N = 7.8 N`
Applying force smaller than the friction force, then the block will not move, because static friction is self adjusting so, it will be equal to 2.3 N
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