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A particle is moving in a circle of radi...

A particle is moving in a circle of radius R with constant speed v, if radius is double then its centripetal force to keep the same speed should be

A

`F/3`

B

`F/2`

C

2F

D

3F

Text Solution

Verified by Experts

The correct Answer is:
A
Centripetal force `=(mv^(2))/r`
`therefore F_(1)/F_(2) = (3r_(1))/r_(1) rArr F_(2) = F/3`
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