Home
Class 12
PHYSICS
The displacement equation of a simple ha...

The displacement equation of a simple harmonic oscillator is given by `y=A sin omegat-Bcos omegat`
The amplitude of the oscillator will be

A

`A-B`

B

`A+B`

C

`sqrt(A^(2)+B^(2))`

D

`A^(2)+B^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`y=Asinwt-Bcoswt`
lt `A=acostheta,B=asintheta`
`a^(2)=A^(2)+B^(2)`
`a=sqrt(A^(2)+B^(2))`
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    PHYSICS WALLAH|Exercise LEVEL-2|28 Videos

  • OSCILLATIONS

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |5 Videos

  • MOVING CHARGES AND MAGNETISM

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |12 Videos

  • RAY OPTICS AND OPTICAL INSTRUMENTS

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |16 Videos

Similar Questions

Explore conceptually related problems

The displacement of a harmonic oscillator is given by x=alpha sin omegat+beta cosomegat . Then the amplitude of the oscillator is,

Simple harmonic oscillations are

The phase of simple harmonic oscillator is

The displacement equation of a particle of medium during wave mation is given by y=A sin omega t-B cos omega t The amplitude of the oscillator will be

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+Asinomegat+Bcosomegat Then the amplitude of its oscillation is given by :

The equation of displacement of a harmonic oscillator is x = 3sin omega t +4 cos omega t amplitude is

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by

The displacement of a simple harmonic oscillator is given by x = 4 cos (2pit+pi//4)m . Then velocity of the oscillator at t = 2 s is

The ratio of the amplitudes of the simple harmonic oscillations given by y_1=Asinomegat and

In a simple harmonic oscillator, at the mean position